ここで、金属と酸素または金属と窒素の結合のイオン性を考えると、窒素のほ

ここで、金属と酸素または金属と窒素の結合のイオン性を考えると、窒素のほうが酸素よりも電気陰性度が小さいため、金属との電気陰性度の差が小さくなる。すなわち、金属と窒素間の結合のほうがイオン性が小さくなるため、式(1-2)から判断するに分極率(α)が大きくなる。そして、式(1-1)から屈折率が大きくなることにつながる。このことから、窒素を含む酸窒化物が酸化物よりも大きい屈折率を持つことが理解できる。実際の屈折率の違いを酸化スズ(SnO2)で確認してみる。Figure. 1-1-3(a)はSnO2と窒素を含んだ酸化スズ(SnO2:N)の各入射光エネルギーに対する屈折率のグラフである[1.8]。凡例脇の10%, 40%といった数値は製膜時の窒素流量を示している。そして、窒素流量があった、つまり窒素を含んだサンプルのほうが窒素をまったく含まないサンプルに対して高い屈折率を示しているのがわかる。また、Fig. 1-1-3(b)は、同じサンプルの消衰係数(k)であるが、窒素を含んだサンプルだと吸収端が小さくなっていることが読み取れる。SnO2系にも窒素によるバンドギャップの減少効果が当てはまっているとわかる。

結果 (英語) 1:

Here, considering the combination of metal and oxygen or metals and nitrogen Ionic nitrogen than oxygen is less than the electronegativity because the difference in electronegativity of metals and is smaller. Namely, judging from the expression (1-2) is the bond between nitrogen and metal ion decreases because the increases the polarizability (Alpha). And from EQ. (1-1) leads to greater refractive index. Having a refractive index oxynitrides, containing nitrogen oxides is greater than can understand. Differences in refractive index of fact checking on Tin oxide (SnO2). Figure. 1-1-3 (a) is a tin oxide SnO2 and nitrogen containing (SnO 2: N) for each [1.8] chart of refraction of incident light energy. Legend aside 10%, 40%, figures indicate manufacture nitrogen flow. And can indicate a high refractive index samples no sample involved had the nitrogen flow rate, this means that nitrogen is nitrogen. Also, read sample containing nitrogen Fig. 1-1-3 (b) is the extinction coefficient (k) of the same sample, but that absorption edge is smaller. Understood and are true to the SnO2 based band gap due to nitrogen reduction.

結果 (英語) 2:

Here, considering the ionic bonds between metal and oxygen, or a metal and nitrogen, because more nitrogen is less electronegative than oxygen, the difference between the electronegativity of the metal is reduced. That is, since more of the bond between the metal and nitrogen becomes smaller ionic polarizability (α) increases to determine from the equation (1-2). And it will lead that the refractive index increases from the equation (1-1). Therefore, oxynitride containing nitrogen can it be appreciated that having a refractive index greater than that of the oxide. I try to check the tin oxide (SnO2) the actual difference in the refractive index. . Figure 1-1-3 (a) tin oxide containing a SnO2 and nitrogen: is a graph of the refractive index with respect to the incident light energy (SnO2 N) [1.8]. 10% of the legend aside, numerical like 40% indicates a nitrogen flow rate during film. Then, there was nitrogen flow rate, that is understood to be that the more samples containing the nitrogen indicates a high refractive index with respect to the sample containing no nitrogen. Also, Fig. 1-1-3 (b), which is the extinction coefficient (k) of the same sample, it can be read that contain nitrogen absorption edge to be the sample is small. Also SnO2 system it knows that the effect of reducing the band gap by nitrogen has held true.

結果 (英語) 3:

Here, the ion of oxygen or nitrogen and metal binding, electronegativity than that of oxygen and nitrogen is small, and the metal electronegativity difference becomes small. That is, because of the coupling between metal and nitrogen ions of boron is reduced, the formula (1) and (2) to determine the polarization ratio. Alpha. The equation (1-1) resulting from a large refractive index. From this, it can be seen that the oxynitride containing nitrogen oxide with high refractive index.The actual refractive index difference SnO tin oxide (2) is tested. Figure 1 with a tin oxide containing nitrogen and SnO 2 SnO 2 N of refractive index for each incident light energy that's got 1.8 graph Numerical value 10 and 40%, respectively, such as the legend is made of a nitrogen flow rate at the time of the film. The nitrogen flow rate, including nitrogen, that is, it can be understood that a high refractive index for the sample of the sample does not contain nitrogen. In addition, Fig 1 (1) (b) (3)As a sample of the extinction coefficient (k), it is understood that the sample containing nitrogen absorption edge is also reduced. Find the true effect of band gap decreased by nitrogen in SnO system.